What children can be born to a woman with a color blindness gene who married a man with normal color vision?

Parents X (A) X (a) × X (A) Y

gametes G: X (A) X (a) X (A) Y

children F1: X (A) X (A), X (A) Y, X (A) X (a), X (a) Y

The sign of color blindness is linked to the X gene, if a woman is a carrier, then she is heterozygous for this trait. The genotype of each of the parents gives two gametes, so this pair may have: a healthy girl, a healthy boy, a girl with a sign of color blindness and a sick boy. Thus, the ratio of healthy and sick children is 3: 1.