What current is consumed by an electric iron at a voltage of 220V if the resistance of its coil in operating mode is 0.12 kΩ?

According to Ohm’s law, the current in the electric iron will be directly proportional to the effective voltage and inversely proportional to the resistance of the coil of the electric iron.

I = U / R, where U is the voltage in the network (U = 220 V), R is the resistance of the electric iron spiral (R = 0.12 kOhm = 120 Ohm).

Let’s calculate the current strength:

I = U / R = 220/120 = 1.83 A.

Answer: The current is 1.83 A.