What depth in the lake corresponds to a water pressure of 50 kPa?

Problem data: P (pressure that the lake water should create) = 50 kPa (50 * 10 ^ 3 Pa).

Reference data: g (acceleration due to gravity) ≈ 10 m / s2; ρw (density of water in the lake) = 1000 kg / m3.

The depth at which the water in the lake will create the required pressure can be expressed from the formula: P = ρw * g * h, whence h = P / (ρw * g).

Let’s calculate: h = 50 * 10 ^ 3 / (1000 * 10) = 5 m.

Answer: The pressure of 50 kPa will be created by the water in the lake at a depth of 5 m.