What distance does the train travel if, after 40 seconds of braking, its speed changes from 36 to 18 km / h?
| May 9, 2021 | education
Task data: t (deceleration duration) = 40 s; V0 (initial train speed) = 36 km / h (in SI system V0 = 10 m / s); V (train speed after braking) = 18 km / h (in SI system V = 5 m / s).
The distance covered by the train under consideration in 40 s of braking is calculated by the formula: S = (V + V0) * t / 2.
Calculation: S = (10 + 5) * 40/2 = 300 m.
Answer: In 40 seconds of braking, the train in question should have covered 300 meters.
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