What EMF of self-induction will arise in a coil with an inductance of 68mH, if the current of 3.8A
| July 5, 2021 | education
What EMF of self-induction will arise in a coil with an inductance of 68mH, if the current of 3.8A in it decreases to zero in 0.012s.
To find out the value of the self-induction EMF that has arisen in the indicated coil, we apply the formula: | εsi | = L * ΔI / Δt, where L is the inductance of the indicated coil (L = 68 mH = 0.068 H); ΔI – change in current (ΔI = 3.8 A, the current decreased to zero from 3.8 A); Δt – time change (Δt = 0.012 s).
Let’s calculate: | εsi | = L * ΔI / Δt = 0.068 * 3.8 / 0.012 = 21.5 (3) V.
Answer: An EMF of self-induction equal to 21.5 (3) V should have appeared in the coil.
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