What energy is required to melt a 4 kg steel cylinder at the melting temperature?
| March 3, 2021 | education
Given:
m = 4 kilograms is the mass of the steel cylinder;
q = 84 kJ / kg = 84000 Joule / kilogram – specific heat of fusion of steel.
It is required to determine Q (Joule) – what energy is needed to melt a steel cylinder of mass m.
Since, according to the condition of the problem, the steel cylinder is already at the melting temperature, we will find the required energy by the following formula:
Q = q * m = 84000 * 4 = 336000 Joules = 336 kJ.
Answer: to melt a steel cylinder with a mass of 4 kilograms, an energy of 336 kJ is required.
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