What energy is required to melt a 4 kg steel cylinder taken at the melting temperature?

The amount of heat required to melt steel can be calculated by the formula (since the steel cylinder is taken at the melting temperature, additional heating is not required):

Q = λ * m, where λ is the specific heat of melting of steel (λ = 0.84 * 105 J / (kg * K)), m is the mass of the steel cylinder (m = 4 kg).

Let’s calculate the required amount of heat:

Q = λ * m = 0.84 * 105 * 4 = 336000 J = 336 kJ.

Answer: It takes 336 kJ of energy to melt a steel cylinder.



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