What force acts on the bottom of a 500 cm² vessel if the liquid poured into it produces

What force acts on the bottom of a 500 cm² vessel if the liquid poured into it produces a pressure of 800 Pa at the bottom?

Liquid pressure at the bottom of the vessel is the ratio of the acting force that will press on the bottom of the vessel to the value of the area of the bottom of the vessel.
P = F / S, where P is the pressure of the liquid at the bottom (P = 800 Pa); F is the force of pressure on the bottom (N), S is the area of the bottom of the vessel (S = 500 cm ^ 2 = 500 * 10 ^ -4 m ^ 2).
Let us express and calculate the value of the acting force:
F = P * S = 800 * 500 * 10 ^ -4 = 40 N
Answer: A force of 40 N acts on the bottom of the vessel.