What force must be applied to a body 60 cm long, 20 cm wide, 10 cm high made of lead to keep it in the water?

The buoyancy force of Archimedes and the force of gravity act on the body in the water, to overcome which the force is expended to keep the body in the water.
Р = mg – ρgV, where m is body weight (m = ρwith * V, where ρwith is lead density (ρwith = 11350 kg / m ^ 3, V is body volume (V = 0.6 * 0.2 * 0, 1 = 0.012 m ^ 3))), g is the acceleration of gravity (g = 10 m / s ^ 2), ρ is the density of water (ρ = 1000 kg / m ^ 3).
P = mg – ρgV = ρw * V * g – ρgV = 11350 * 0.012 * 10 – 1000 * 10 * 0.012 = 1362 – 120 = 1242 N.
Answer. To hold the body, a force of 1242 N is needed.