What force must be applied to a spring with a stiffness of 40 Newton meters to stretch it by 5 cm?

The force applied to stretch the spring will be equal to the opposing elastic force, which can be calculated using the formula:

F = F = k * ∆l, where k is the stiffness of the spring (k = 40 N / m); ∆l – spring tension (∆l = 5 cm = 0.05 m).

Let’s make a calculation:

Fcont. = k * ∆l = 40 * 0.05 = 2 N.

Answer: A force of 2 N. must be applied to the spring.

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