What force must be applied to hold a 0.7 m3 steel rail in the water?
| January 27, 2021 | education
Data: V (steel lath volume) = 0.7 m3; ρw (density of water in which the rail is immersed) = 1000 kg / m3; g (acceleration due to gravity) = 9.81 m / s2; ρst (steel density) = 7800 kg / m3.
Strength for holding the rail: F = P – Fa = ρst * V * g – ρw * g * V = (ρst – ρw) * g * V = (7800 – 1000) * 9.81 * 0.7 = 46695.6 H ≈ 46.7 kN.
Answer: A force of 46.7 kN is required on the rail.
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