What force must be applied to hold a piece of granite with a volume of 4 * 10 ^ 3m ^ 3 under water.

| March 8, 2021 | education

Given:

V = 4 * 10 ^ 3 cubic meters – the volume of a piece of granite immersed in water;

ro1 = 2600 kilograms per cubic meter – the density of granite;

ro = 1000 kilograms per cubic meter – the density of water.

It is required to determine F (Newton) – what force must be applied to keep a piece of granite in water.

Find the mass of a piece of granite:

m = V * ro1 = 4 * 10 ^ 3 * 2600 = 10.4 * 106 kilograms.

Then, to determine the strength, you must use the following formula:

F = F gravity – Farchimedes;

F = m * g – ro * V * g, where g = 10 Newton / kilogram (approximate value);

F = g * (m – ro * V);

F = 10 * (10.4 * 10 ^ 6 – 1000 * 4 * 10 ^ 3) = 10 * (10.4 * 10 ^ 6 – 4 * 10 ^ 6) = 10 * 6.4 * 10 ^ 6 = 6.4 * 10 ^ 7 Newton (64 MN).

Answer: to keep a piece of granite in water, you need to apply a force equal to 6.4 * 10 ^ 7 Newton (64 MN).

Given:

V = 4 * 10 ^ 3 cubic meters – the volume of a piece of granite immersed in water;

ro1 = 2600 kilograms per cubic meter – the density of granite;

ro = 1000 kilograms per cubic meter – the density of water.

It is required to determine F (Newton) – what force must be applied to keep a piece of granite in water.

Find the mass of a piece of granite:

m = V * ro1 = 4 * 10 ^ 3 * 2600 = 10.4 * 106 kilograms.

Then, to determine the strength, you must use the following formula:

F = F gravity – Farchimedes;

F = m * g – ro * V * g, where g = 10 Newton / kilogram (approximate value);

F = g * (m – ro * V);

F = 10 * (10.4 * 10 ^ 6 – 1000 * 4 * 10 ^ 3) = 10 * (10.4 * 10 ^ 6 – 4 * 10 ^ 6) = 10 * 6.4 * 10 ^ 6 = 6.4 * 10 ^ 7 Newton (64 MN).

Answer: to keep a piece of granite in water, you need to apply a force equal to 6.4 * 10 ^ 7 Newton (64 MN).



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