What force must be applied to keep a granite slab weighing 2.6 tons in water? Density of granite is 2600 kg / m3

Given:

m = 2.6 tons = 2600 kilograms – the mass of a granite slab immersed in water;

ro1 = 2600 kilograms per cubic meter – the density of granite;

ro = 1000 kilograms per cubic meter – the density of water.

It is required to determine F (Newton) – what force must be applied to keep the granite slab in water.

Let’s find the volume that the granite slab occupies:

V = m / ro = 2600/2600 = 1m3.

Then, to determine the strength, you must use the following formula:

F = F gravity – Farchimedes;

F = m * g – ro * V * g, where g = 10 Newton / kilogram (approximate value);

F = g * (m – ro * V);

F = 10 * (2600 – 1000 * 1) = 10 * (2600 – 1000) = 10 * 1600 = 16000 Newtons (16 kN).

Answer: To keep a granite slab in water, you need to apply a force equal to 16,000 Newtons (16 kN).



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