What force must be applied to lift a 300 kg stone with a volume of 115 dm3 under water?
| April 20, 2021 | education
Stone volume in cubic meters:
V = 115 dm3 = 0.115 m3.
The buoyant force FА = ρgV, where ρ is the density of water, g is the acceleration of gravity.
The force of gravity acting on the stone:
Fт = mg.
The force with which the stone presses to the bottom:
Fт – FА = g (m- ρV) = 10 m / s2 * (300 kg – 1000 kg / m3 * 0.115 m3) = 10 * 185 N = 1850 N.
Answer: You need to apply a force of 1850 N.
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