What force must be applied to lift a body with a mass of 3 kg and a volume of 200 cm ^ 3 in gasoline?

To determine the value of the force required to lift the body in question in gasoline, we use the formula: F = Fт – Fa (projection onto the vertical axis) = m * g – ρb * g * V = (m – ρb * V) * g.

Constants and variables: m – body weight (m = 3 kg); ρb is the density of gasoline (ρb = 710 kg / m3); V – body volume (V = 200 cm3 = 200 * 10 ^ -6 m3); g – acceleration due to gravity (g ≈ 9.8 m / s2).

Calculation: F = (m – ρb * V) * g = (3 – 710 * 200 * 10 ^ -6) * 9.8 ≈ 28 N.

Answer: To lift the body in question in gasoline, a force of 28 N is required.