What force must be applied to lift a stone with a mass of 600 kg and a volume of 0.23 m ^ 3 under water?

A stone in water is acted upon by the force of Archimedes and the force of gravity. To lift a stone in water, a force must be applied in the direction of the Archimedes force to compensate for the effect of gravity.
F = Fт – Fа = m * g – ρ * g * V, where m is the mass of the stone (m = 600 kg), g is the acceleration of gravity (g = 9.8 m / s ^ 2), ρ is the density of water (ρ = 1000 kg / m ^ 3), V is the volume of the stone (V = 0.23 m ^ 3).
Required Strength:
F = m * g – ρ * g * V = 600 * 9.8 – 1000 * 9.8 * 0.23 = 5880 – 2254 = 3626 N.
Answer: It is necessary to apply force F = 3625 N.