What force must be applied to lift a stone with a mass of 600 kg and a volume of 0.23 m3 under water.

Given:

m = 600 kilograms is the mass of a stone lying under water;

V = 0.23 cubic meters – the volume of the stone;

ro = 1000 kilograms / cubic meter – density of water.

It is required to determine F (Newton) – what force must be applied to lift the stone.

We will assume that the stone must be lifted evenly at a constant speed. Then, according to Newton’s first law:

F = F gravity – Farchimedes;

F = m * g – ro * V * g, where g = 10 Newton / kilogram (approximate value);

F = g * (m – ro * V);

F = 10 * (600 – 1000 * 0.23) = 10 * (600 – 230) = 10 * 370 = 3700 Newtons.

Answer: to lift a stone out of the water, you need to apply a force equal to 3700 Newtons.