What force must be applied to stretch the wire by 1 mm if the stiffness of the wire is 100 N / m?
| September 19, 2021 | education
Initial data: Δl (wire elongation value) = 1 mm = 1 * 10-3 m; k (coefficient of spring stiffness) = 100 N / m.
The force applied to the wire can be determined from Hooke’s law by the following formula: F = -Fcont = k * Δl.
Let’s perform the calculation: F = 100 * 1 * 10-3 = 0.1 N.
Answer: To stretch the wire, you need to apply a force of 0.1 N.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
