What force must be applied to the end of the wire with a coefficient of elasticity of 100 kN / m in order to stretch it by 2 mm.

The force that was applied to the end of the wire to stretch it will be equal to the elastic force of this wire, which we calculate by the formula:

F = F = k * ∆l, where k is the stiffness of the wire (k = 100 kN / m = 100 * 10 ^ 3 N / m); ∆l – the amount of deformation (tension) of the wire (∆l = 2 mm = 2 * 10 ^ -3 m).

Let’s make a calculation:

Fcont. = k * ∆l = 100 * 10 ^ 3 * 2 * 10 ^ -3 = 200 N.

Answer: A force of 200 N must be applied to the end of the spring.