What force must be applied to the ends of the spring, with a stiffness of 0.2 kN / m, so that its elongation is equal to 3 cm?
| July 8, 2021 | education
Initial data: k (coefficient of stiffness of the considered spring) = 0.2 kN / m (200 N / m); Δx (required spring extension) = 3 cm (0.03 m).
The force that is required to be applied to the ends of the spring under consideration is determined by the formula: F = -Fcont. = k * Δх.
Calculation: F = 200 * 0.03 = 6 N.
Answer: A force of 6 N is required to be applied to the ends of the spring in question.
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