What force must be applied to the left arm of the lever when it is in equilibrium, if the length

What force must be applied to the left arm of the lever when it is in equilibrium, if the length of this arm is 0.8 m, the length of the second arm is 1 m, the force acting on the right arm is 16 Newtons.

As we know from the school physics course, the equilibrium position of the lever can be described in the form of the following formula:

F1 / F2 = l2 / l1.

Let us determine what will be the value of the force that should act on the lever arm 0.8 meters long, when from the condition of our problem it is precisely known that a force of 16 N acts on the other arm, whose length is 1 meter:

F1 = F2 * l2 / l1;

16 * 1: 0.8 = 20

Answer: Under such initial conditions, a force of 20 N. should act on the lever arm 0.8 meters long.