What force must be applied to the steel wire so that it lengthens by 1.5 mm if its stiffness is 30 * 10 ^ 3n / m?

Initial data: Δl (required steel wire elongation) = 1.5 mm; k (stiffness coefficient of steel wire) = 30 * 10 ^ 3 N / m.

SI system: Δl = 1.5 mm = 1.5 * 10 ^ -3 m.

The value of the force that needs to be applied to the steel wire is determined using Hooke’s law: F = -Fcont. = k * Δl.

Let’s make a calculation: F = 30 * 10 ^ 3 * 1.5 * 10 ^ -3 = 45 N.

Answer: A force of 45 N will need to be applied to the steel wire.