What gain in power can be obtained on a hydraulic machine in which the cross-sectional area of the small
| May 6, 2021 | education
What gain in power can be obtained on a hydraulic machine in which the cross-sectional area of the small piston is 2 dm2, and the cross-sectional area of the larger piston is 50 dm2.
To find out the power gain obtained during the operation of the specified hydraulic machine, consider the formula: k = Sbp / Smp, where Sbp is the cross-sectional area of the larger piston (Sbp = 50 dm2); Smp – cross-sectional area of the smaller piston (Smp = 2 dm2).
Let’s perform the calculation: k = Sbp / Smp = 50/2 = 25 p.
Answer: When the specified hydraulic machine is operated, the power gain will be 25 times.
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