What is the acceleration due to gravity at a height equal to half the Earth’s radius?

Data: h (height above the Earth’s surface) = 0.5Rz.

Constants: G (gravitational constant) = 6.67 * 10 ^ -11 m3 / (kg * s2); M (mass of the Earth) = 5.97 * 10 ^ 24 kg; by the condition R (radius of the Earth) = 6400 km = 6400 * 10 ^ 3 m.

Free fall acceleration at a given height can be calculated using the formula: g = G * M / (h + R) ^ 2 = G * M / (0.5R + R) ^ 2 = G * M / (1.5R) ^ 2 …

Let’s perform the calculation: g = 6.67 * 10 ^ -11 * 5.97 * 10 ^ 24 / (1.5 * 6400 * 10 ^ 3) ^ 2 = 4.32 m / s2.

Answer: A. The acceleration of gravity is 4.32 m / s2 (4.4 m / s2).