# What is the acceleration of a bar sliding along an inclined plane if its angle of inclination is 30 ‘degrees

December 29, 2020 | education

| **What is the acceleration of a bar sliding along an inclined plane if its angle of inclination is 30 ‘degrees and the coefficient of friction is 0.15?**

Expand the acceleration g into two axes: OX and OY

g (y) = g * cos a

g (x) = g * sin a

Friction force (Ftr)

Ftr = mu * m * g * cos a

F tightness by OX = F1 = mg * sin a

According to Newton’s Laws:

F1-Ftr = m * a

g * sin a – mu * g * cos a = a (acceleration)

Answer: g * sin a – mu * g * cos a = a (acceleration)

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