What is the acceleration of a bullet that, having pierced a wall 35 cm thick
| September 17, 2021 | education
What is the acceleration of a bullet that, having pierced a wall 35 cm thick, reduced its velocity from 800 m / s to 400 m / s?
V1 = 800m / s,
V2 = 400m / s,
S = 35cm = 0.35m;
a -?
With uniformly accelerated motion, the distance traveled can be found from the formula:
S = (V2 ^ 2 – V1 ^ 2) / (2 * a);
From here we get:
a = (V2 ^ 2 – V1 ^ 2) / (2 * S);
a = 400 * 1200 / 0.7 = 685700m / s ^ 2.
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