What is the acceleration of a load weighing 500 kg, which is lowered with the help

What is the acceleration of a load weighing 500 kg, which is lowered with the help of a cable, if the tension force of the cable is 4000N?

Task data: m (weight of the load, which is lowered on the cable) = 500 kg; Fnat (tension force of the cable used) = 4000 N; air resistance is not taken into account.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The acceleration of the lowered load is expressed from the equality: m * a = Ft – Fnat, whence a = (Ft – Fnat) / m = (m * g – Fnat) / m.

Let’s make a calculation: a = (500 * 10 – 4000) / 500 = 2 m / s2.

Answer: The acceleration of the lowered load is 2 m / s2.