What is the amount of a substance of aluminum hydroxide weighing 357 g

univerkov | September 25, 2021 | education

Given:
m (Al (OH) 3) = 357 g

Find:
n (Al (OH) 3) -?

1) M (Al (OH) 3) = Mr (Al (OH) 3) = Ar (Al) * N (Al) + Ar (O) * N (O) + Ar (H) * N (H) = 27 * 1 + 16 * 3 + 1 * 3 = 78 g / mol;
2) n (Al (OH) 3) = m / M = 357/78 = 4.6 mol.

Answer: The amount of substance Al (OH) 3 is 4.6 mol.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.