What is the amount of ice with a mass of -25g in the heat absorbed during melting

1) What is the amount of ice with a mass of -25g in the heat absorbed during melting, if its initial temperature is -15 degrees. 2) 0.5 liters of water boiled out of the kettle how much heat was spent on it.

Constants: 1) С (specific heat capacity of ice) = 2100 J / (kg * K); λ (specific heat of melting of ice) = 3.4 * 10 ^ 5 J / kg; 2) L (specific heat of vaporization of water) = 2.3 * 10 ^ 6 J / kg.

1) Q = Q1 (heating 25 g of ice from a temperature of -15 ºС to 0 ºС) + Q2 (melting 25 g of ice) = С * m * Δt + λ * m = 2100 * 0.025 * (0 – (-15)) + 3.4 * 10 ^ 5 * 0.025 = 9287.5 J.

2) Q (vaporization of 0.5 l (0.5 kg) of water) = L * m = 2.3 * 10 ^ 6 * 0.5 = 1.15 * 10 ^ 6 J = 1.15 MJ.