What is the amount of work done when moving a 20 nC charge in an electric field from a point with

What is the amount of work done when moving a 20 nC charge in an electric field from a point with a potential of 600 V to a point with a potential of 100 V?

Initial data: q (value of the displaced charge) = 20 nC (20 * 10 ^ -9 C); φ1 (field potential at the starting point) = 600 V; φ2 (field potential at the end point) = 100 V.

The amount of work when moving the charge is determined by the formula: A = q * (φ1 – φ2).

Let’s make the calculation: A = 20 * 10 ^ -9 * (600 – 100) = 10 * 10 ^ -6 J (10 μJ).

Answer: When moving the charge, a work of 10 μJ was done.