What is the ampere force of the acting side of the magnetic field on a conductor 2 m

What is the ampere force of the acting side of the magnetic field on a conductor 2 m long with a current of 3a, which is a magnetic field with an induction of 0.4 T.

L = 2 m.

I = 3 A.

B = 0.4 T.

Fump -?

On a conductor of length L, which is in a magnetic field with induction B, and through which an electric current flows with a current strength I, the Ampere force Famp acts: Famp = I * B * L.

Famp = 3 A * 0.4 T * 2 m = 2.4 N.

Answer: Ampere force Famp = 2.4 N. acts on the conductor with current.



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