What is the angle at the base of an isosceles triangle if the angle at the apex is 80 °?

1) Find the sum of the angles at the base of a given isosceles triangle: 2α = 180º – γ, where 180º is the sum of all angles; γ – value of the angle at the vertex (γ = 80º).
2α = 180º – γ = 180º – 80º = 100º.
2) Let’s calculate the value of the angles at the base: α = 100º / 2 = 50º.
Answer: The angle at the base of a given isosceles triangle is 50º.



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