What is the Archimedean force acting from the atmospheric air on a person with a volume of 50 dm³?

What is the Archimedean force acting from the atmospheric air on a person with a volume of 50 dm³? air density 1.3 kg / m³

These tasks: V (the volume of the person under consideration) = 50 dm3 (in SI V = 50 * 10-3 m3).

Reference data: g (acceleration due to gravity) ≈ 9.8 m / s2; according to the condition ρw (density of atmospheric air) = 1.3 kg / m3.

The Archimedean force acting on the person in question is calculated by the formula: Fa = ρw * g * V.

Let’s calculate: Fa = 1.3 * 9.8 * 50 * 10-3 = 0.637 N.

Answer: An Archimedes force of 0.637 N. acts on the person under consideration from the atmospheric air.