What is the Archimedean force acting from the atmospheric air on a person with a volume of 50 dm ^ 3.

V = 50 cubic decimeters – the volume of the human body;

g = 10 Newton / kilogram – acceleration of gravity;

ro = 1.3 kilograms / cubic meter – air density (under normal conditions).

It is required to determine Farchimedes (Newton) – the Archimedean force acting on a person from the air.

Let’s convert the units of measurement of volume from cubic decimeters to cubic meters:

V = 50 dm3 = 50 * 10-3 = 50/1000 = 0.05 cubic meters.

Then, to determine the Archimedean force, you must use the following formula:

Farchimedes = ro * g * V = 1.3 * 10 * 0.05 = 1.3 * 0.5 = 0.65 Newton.

Answer: from the side of the atmosphere, an Archimedean force acts on a person, equal to 0.65 Newton.