What is the Archimedean force acting in kerosene on a cast-iron ball weighing 1.4 kg?

Initial data: m (mass of the cast iron ball) = 1.4 kg.

Reference values: ρк (kerosene density) = 800 kg / m3; ρh (average density of cast iron) = 7000 kg / m3; g (acceleration due to gravity) = 10 m / s2.

1) Determine the volume of the cast iron ball: V = m / ρh = 1.4 / 7000 = 0.0002 m3.

2) Calculate the force of Archimedes, which acts on a given cast-iron ball in kerosene: Fа = ρк * g * V = 800 * 10 * 0.0002 = 1.6 N.

Answer: An Archimedes force of 1.6 N. acts on a cast-iron ball in kerosene.



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