What is the Archimedean force acting on a 5 m3 ball in air?

Problem data: V (volume of the considered sphere) = 5 m3.

Reference data: ρv (air density at standard conditions (T = 0 ºС)) = 1.293 kg / m3; g (acceleration due to gravity) = 9.81 m / s2.

The force of Archimedes, which acts on the ball under consideration, can be determined by the formula: Fа = ρw * g * V.

Let’s make a calculation: Fа = 1.293 * 9.81 * 5 ≈ 63.42 N.

Answer: An Archimedes force of 63.42 N. acts on the ball under consideration.

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