What is the Archimedean force acting on a 5m3 ball in air?

Problem data: V (volume of the taken ball) = 5 m3.

Reference values: ρv (density that air has under standard conditions for gases, t = 0 ºС) = 1.292 kg / m3; g (acceleration due to gravity) = 9.81 m / s2.

We calculate the Archimedean force acting on a given ball by the formula: Fa = ρw * g * V.

Let’s calculate: P = 1.292 * 9.81 * 5 ≈ 63.37 N.

Answer: An Archimedean force of 63.37 N. acts on a taken ball in the air.

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