What is the Archimedean force acting on a piece of iron with a volume of 0.005 m3 in water?
| May 4, 2021 | education
These tasks: V (volume of the considered piece of iron) = 0.005 m3.
Reference data: ρw (water density) = 1000 kg / m3; g (acceleration due to gravity) ≈ 9.8 m / s2.
The Archimedean force acting on the considered piece of iron in water can be calculated by the formula: Fa = ρw * g * V.
Let’s calculate: Fa = 1000 * 9.8 * 0.005 = 49 N.
Answer: An Archimedean force of 49 N. acts on the piece of iron under consideration.
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