What is the Archimedean force acting on a wooden block with a volume of 250 cm³,

What is the Archimedean force acting on a wooden block with a volume of 250 cm³, if it is submerged in water by 1/4 of its volume?

These tasks: V (the volume of the taken wooden block) = 250 cm3 (in SI V = 250 * 10-6 m3); Vp (part of the bar immersed in water) = 1/4 V.

Reference values: ρw (water density) = 1000 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.

The Archimedes force acting on a taken wooden block is calculated by the formula: Fa = ρw * g * Vp = 1/4 * ρw * g * V.

Let’s calculate: Fa = 1/4 * 1000 * 10 * 250 * 10-6 = 0.625 N.

Answer: An Archimedes force of 0.625 N. acts on the taken wooden block.