What is the Archimedean force that acts on a 10 cm2 ball completely (by 3/4) submerged in water (kerosene)?

Given: V (the volume of the taken ball) = 10 cm3 (in the SI system V = 10 * 10-6 m3).

Constants: ρw (water density) = 1000 kg / m3; ρк (kerosene density) = 800 kg / m3; g (acceleration due to gravity) ≈ 9.8 m / s2.

1) Full immersion in water: Fa = ρw * g * V = 1000 * 9.8 * 10 * 10-6 = 0.098 N.

2) Immersion of the ball by 3/4 of its volume in kerosene (Vp = 3/4 V): Fa = ρk * g * Vp = 3/4 * 800 * 9.8 * 10 * 10-6 = 0.0588 N.

Answer: When immersed in water, the Archimedes force is 0.098 N, when immersed in kerosene – 0.0588 N.