What is the area of a rectangle ABCD if its sides are 5: 7 and one side is 3 cm larger than the other?

1) Find the sides of the rectangle. If they are 5: 7, then this means that one side contains 5 parts of length, and the other side contains 7 of the same parts of length.

Let the length of one part of the length be x cm, then the length of the first side of the rectangle is 5x cm, and the length of the second side is 7x cm.By the condition of the problem, it is known that the length of one side of the rectangle is greater than the length of the other side of the triangle by (7x – 5x) cm or by 3 cm. Let’s compose an equation and solve it.

7x – 5x = 3;

2x = 3;

x = 3: 2;

x = 1.5 (cm);

5x = 1.5 * 5 = 7.5 (cm) – first side;

7x = 1.5 * 7 = 10.5 (cm) – the second side.

2) Find the area of ​​the rectangle using the formula S = a * b.

S = 7.5 * 10.5 = 78.75 (cm ^ 2).

Answer. 78.75 cm ^ 2.



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