What is the area of a rhombus if its diagonals are 10 and 16?

The diagonals of the rhombus intersect at right angles and are halved at the intersection. The formula for the area of a rhombus in terms of the diagonals is the half-product of its diagonals.

S = 1/2 * d1 * d2.

AC = d1 = 10, BD = d2 = 16.

thus: S = 1/2 * d1 * d2 = 1/2 * 10 * 16 = 80.

Answer: The area of a rhombus with diagonals 10 and 16 is 80.



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