What is the area of a rhombus with a side of 8 cm and an angle of 60 degrees?

The area of a rhombus can be defined as the product of the square of the side and the sine of the angle between them: S = a2 * sin α.
By condition, the side is equal to a rhombus of 8 cm, and the angle between the sides is 60 °, which means
S = 82 * sin 60 = 64 * √3 / 2 = 32√3 ≈ 55.43.
The required area of the rhombus is 32√3 or 55.43 cm2.



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