What is the area of a triangle with vertices A (5; 3), B (5; –4) and C (0; –3)?
| March 16, 2021 | education
1. By the condition of the problem, the coordinates of the vertices of the triangle A (5; 3), B (5; -4), C (0; -3) are known.
2. The area S of the triangle will be calculated as half of the product of the base and the height.
In a given triangle ABC, side AB is perpendicular to the coordinate axis Ox, and therefore the projection of point C onto the axis Oy will be the height lowered to the side AB and is equal to 3 + 5 = 8
AB is the sum of the ordinates of points A and B, that is, 3 + 4 = 7.
Area S = 1/2 * 8 * 7 = 28 units ².
Answer: The area of a triangle is 28 units².
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