What is the area of the soles of a boy’s shoes if his weight is 48 kg and he exerts a pressure of 15 kPa?

Let’s write down given from the condition:

m = 48 kg (boy’s weight);

p = 15 * 10 ^ 3 Pa (pressure on the sole of the shoe);

Find S -? (boy’s shoe area).

Decision:

By definition, pressure can be found as the ratio of force to area:

P = F / S, where F in our case is the body weight, then F = m * g.

Let us express the area from the first formula and get:

P = mg / S;

S = mg / p;

Substitute the value and calculate:

S = (48 * 10) / (15 * 10 ^ 3) = 0.032 m ^ 2 = 0.032 * 10 ^ 4 = 320 cm ^ 2.

Answer: the area of the sole of the boy’s shoes is 320 cm ^ 2.