What is the average kinetic energy of gas molecules at a temperature of t = 47 ° C?
| December 17, 2020 | education
Energy:
E = 3/2 (kT)
k = 1.38 * 10 (-23) J / K-Boltzmann constant
T = t + 273 = 27 + 273 = 300R temperature in Kelvin
I substitute in the formula
E = 3 * 1.38 * 10 (-23) * 300K / 2 = 6.21 * 10 (-21) J
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