What is the average kinetic energy of the thermal motion of molecules of a monatomic gas at a temperature of 145K?
| February 25, 2021 | education
To determine the value of the average kinetic energy of the molecules of the indicated gas, we apply the following formula: Ek = 3/2 * k * T.
Data: k – Boltzmann’s constant (k ≈ 1.381 * 10 ^ -23 J / K); T is the temperature of the specified gas (T = 145 K).
Calculation: Ek = 3/2 * k * T = 3/2 * 1.381 * 10 ^ -23 * 145 = 300.3675 * 10 ^ -23 J ≈ 3 sJ.
Answer: The average kinetic energy of the molecules of the indicated gas is 3 zJ.
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