What is the average speed of a car if in the first 2 hours it traveled 60 km and the next 2 hours

What is the average speed of a car if in the first 2 hours it traveled 60 km and the next 2 hours moved at a speed of 40 km / h?

t1 = 2 h.

S1 = 60 km.

t2 = 2 h.

V2 = 40 km / h.

Vav -?

To find the average speed Vav, the car must divide the entire path S by the time it passes the movement t: Vav = S / t.

The travel time of the entire path is expressed by the sum: t = t1 + t2, where t1 is the time of movement on the first half of the path, t2 is the time of movement on the second half of the path.

t = 2 h = 2 h = 4 h.

The entire path S traveled by the car is expressed by the sum: S = S1 + S2.

The second part of the path S2 is expressed by the formula: S2 = V2 * t2.

S = 60 km + 40 km / h * 2 h = 140 km.

Vav = 140 km / 4 h = 35 km / h.

Answer: the average vehicle speed was Vav = 35 km / h.