What is the barometer reading at the height of the 540m tower if the barometer at the bottom

What is the barometer reading at the height of the 540m tower if the barometer at the bottom of the tower shows that the pressure is 100674pa?

Let h1 = 540 m, p1 = 100641 Pa.

The pressure of the column of air can be calculated in the same way as the column of liquid according to the well-known formula:

p = ro * g * h.

ro is the density of air, equal to 1.29 kg / m ^ 3.

The pressure at the top of the tower will be p2 = ro * g * h1.

Thus, the pressure difference at the top and bottom of the tower will be p1 – p2 = p1 – ro * g * h1. Substitute the available data into the resulting formula and calculate:

p = 100641 – 1.29 * 9.8 * 540 = 93814.3 Pa.

Answer: the pressure on the 540 m tower will be equal to 93,814.3 Pa.