What is the capacitance of the capacitor if the charge of the capacitor is 10 nC and the voltage is 20 kV?

To find the value of the electrical capacity of the specified capacitor, you must apply the formula: C = q / U.

Constants and variables: q – charge value (q = 10 nC = 10-8 C); U is the effective voltage across the capacitor (U = 20 kV = 2 * 10 ^ 4 V).

Calculation: C = q / U = 10 ^ -8 / (2 * 10 ^ 4) = 0.5 * 10 ^ -12 F.

Answer: The indicated capacitor, according to the calculation, has an electrical capacity of 0.5 pF.



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